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Standard XII

Chemistry

Dehydrohalogenation for Alkenes

An alkybromid...

Question

An alkybromide(A) On treatment with Na and ether gives a hydrocarbon (B). (B) on treatment with HBr and peroxide gives $B r - (C H_{2})_{6} - B r$ compound (A) is

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Solution

The correct option is B

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Similar questions

An alkybromide(A) On treatment with Na and ether gives a hydrocarbon (B). (B) on treatment with HBr and peroxide gives $B r - (C H_{2})_{6} - B r$ compound (A) is

Q. Pick out the correct reactions:

A . C H_{3} - C H = C H_{2} + H C l ⟶ C H_{3} - C | C l H - C H_{3}

B . C H_{3} - C H = C H_{2} + H B r ⟶ C H_{3} - C H_{2} - C H_{2} B r

C . C H_{3} - C H = C H_{2} + H B r p e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} - B r

D . C H_{3} - C H = C H_{2} + H I p e r o x i d e - ---- \to C H_{3} - C | I H - C H_{3}

Q. Select the member of each pair that shows faster rate of

S_{N} 2

reaction with

K I

in acetone.

(a)

C H_{3} - C H_{2} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H ∣ C H_{3} - C H_{2} - C l

(I) (I I)

(b)

C H_{3} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H_{2} - C H_{2} - B r

(I) (I I)

(c)

C H_{3} - C H ∣ C H_{3} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H_{3} ∣ C ∣ C H_{3} - C H_{2} C l

(I) (I I)

(d)

C H_{3} - C H_{2} - C H_{2} - B r ∣ C H - C H_{3} a n d C H_{3} - C H_{3} ∣ C H - C H_{2} - B r ∣ C H - C H_{3}

(I) (I I)

C H_{3} - C H_{2} - \oplus C H_{2}

C H_{3} - C H | F - \oplus C H_{2}

C H_{3} - C H | B r - \oplus C H_{2}

C H_{3} - C H | C l - \oplus C H_{2}

Arrange the following carbocations in decreasing order of their stability:

Q. Pick out the correct reactions:

A . C H_{3} - C H = C H_{2} + H C l ⟶ C H_{3} - C | C l H - C H_{3}

B . C H_{3} - C H = C H_{2} + H B r ⟶ C H_{3} - C H_{2} - C H_{2} B r

C . C H_{3} - C H = C H_{2} + H B r p e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} - B r

D . C H_{3} - C H = C H_{2} + H I p e r o x i d e - ---- \to C H_{3} - C | I H - C H_{3}

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An alkybromide(A) On treatment with Na and ether gives a hydrocarbon (B). (B) on treatment with HBr and peroxide gives Br−(CH2)6−Br compound (A) is

The correct option is B

An alkybromide(A) On treatment with Na and ether gives a hydrocarbon (B). (B) on treatment with HBr and peroxide gives $B r - (C H_{2})_{6} - B r$ compound (A) is