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Standard XII

Chemistry

General Mechanism of Electrophilic Aromatic Substitution

An alkybromid...

Question

An alkybromide(A) On treatment with Na and ether gives a hydrocarbon (B). (B) on treatment with HBr and Peroxide gives Br - $(C H_{2})_{6} - B r$ compound (A) is

C H_{3} C H_{2} C H_{2} B r

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C H_{2} = C H - C H_{2} B r

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C H_{3} - C H = C H B r

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C H_{3} - C H_{2} - C H_{2} - C H_{2} B r

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Solution

The correct option is B $C H_{2} = C H - C H_{2} B r$

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Similar questions

An alkybromide(A) On treatment with Na and ether gives a hydrocarbon (B). (B) on treatment with HBr and peroxide gives $B r - (C H_{2})_{6} - B r$ compound (A) is

C H_{3} - C H = C H_{2} + H B r \to

-------- the product is

Q. Pick out the correct reactions:

A . C H_{3} - C H = C H_{2} + H C l ⟶ C H_{3} - C | C l H - C H_{3}

B . C H_{3} - C H = C H_{2} + H B r ⟶ C H_{3} - C H_{2} - C H_{2} B r

C . C H_{3} - C H = C H_{2} + H B r p e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} - B r

D . C H_{3} - C H = C H_{2} + H I p e r o x i d e - ---- \to C H_{3} - C | I H - C H_{3}

Q. Select the member of each pair that shows faster rate of

S_{N} 2

reaction with

K I

in acetone.

(a)

C H_{3} - C H_{2} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H ∣ C H_{3} - C H_{2} - C l

(I) (I I)

(b)

C H_{3} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H_{2} - C H_{2} - B r

(I) (I I)

(c)

C H_{3} - C H ∣ C H_{3} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H_{3} ∣ C ∣ C H_{3} - C H_{2} C l

(I) (I I)

(d)

C H_{3} - C H_{2} - C H_{2} - B r ∣ C H - C H_{3} a n d C H_{3} - C H_{3} ∣ C H - C H_{2} - B r ∣ C H - C H_{3}

(I) (I I)

	Column I		Column II
A	$C H_{3} - C H B r - C D_{3}$ /on treatement with alc.KOH gives $C H_{2} = C H - C D_{3}$ as a major product	P	E1 reaction
B	$P h - C H B r - C H_{3}$ reacts faster than $P h - C H B r - C D_{3}$	Q	E2 reaction
C	$P h - C H_{2} - C H_{2} - F$ on treatement with $C_{2} H_{5} O D / C_{2} H_{5} O^{-}$ gives $P h - C D = C H_{2}$ as the major product	R	E1cB reaction
D	$P h - C H_{2} - C H_{2} - B r$ and $P h - C D_{2} - C H_{2} - B r$ react with same rate	S	First order reaction

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An alkybromide(A) On treatment with Na and ether gives a hydrocarbon (B). (B) on treatment with HBr and Peroxide gives Br - (CH2)6−Br compound (A) is

The correct option is B CH2=CH−CH2Br

An alkybromide(A) On treatment with Na and ether gives a hydrocarbon (B). (B) on treatment with HBr and Peroxide gives Br - $(C H_{2})_{6} - B r$ compound (A) is

The correct option is B $C H_{2} = C H - C H_{2} B r$