An alkyl bromide (A) forms Grignard reagent which on treatment with water, yields n-hexane. (A) On treatment with sodium forms 4,5-diethyloctane. (A) is:

C H_{3} - (C H_{2})_{5} - B r

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C H_{3} - (C H_{2})_{3} - C H B r - C H_{3}

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C H_{3} - (C H_{2})_{2} - B r | C H - C H_{2} - C H_{3}

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C H_{3} - (C H_{2})_{2} - B r | C H - C H = C H_{2}

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Solution

The correct option is C $C H_{3} - (C H_{2})_{2} - B r | C H - C H_{2} - C H_{3}$

Grignard reagent is a strong base and it is easily protonated to form alkane.
Alkyl bromide undergoes wurtz reaction to give symmetrical alkane.

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An alkyl bromide (A) forms Grignard reagent which on treatment with water, yields n-hexane. (A) On treatment with sodium forms 4,5-diethyloctane. (A) is:

The correct option is C CH3−(CH2)2−Br|CH−CH2−CH3 Grignard reagent is a strong base and it is easily protonated to form alkane. Alkyl bromide undergoes wurtz reaction to give symmetrical alkane.

The correct option is C $C H_{3} - (C H_{2})_{2} - B r | C H - C H_{2} - C H_{3}$

Grignard reagent is a strong base and it is easily protonated to form alkane.
Alkyl bromide undergoes wurtz reaction to give symmetrical alkane.