The $K_{s p}$ of $A g_{2} C r O_{4}$ is $1.1 \times 10^{- 12}$ at 298K. The solubility (in mol/L) of $A g_{2} C r O_{4}$ in 0.1M $A g N O_{3}$ solution is:

Q. An electron is moving in a circular path of radius

5.1 \times 10^{- 11}

m at a frequency of

6.8 \times 10^{15}

revolutions/sec. The equivalent current is approximately equal to _______.

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An α−particle travels in a circular path of radius 0.45 m in a magnetic field B=1.2 Wb/m2 with a speed of 2.6×102 m/s. The period of revolution of the α particle is

The correct option is A 1.1×10−7 sThe time period of revolution of α-particle is:T=2πmqB=2πrv=2×3.14×0.452.6×107=1.08×10−7sec

An $α -$ particle travels in a circular path of radius $0.45 m$ in a magnetic field $B = 1.2 W b / m^{2}$ with a speed of $2.6 \times 10^{2} m / s$ . The period of revolution of the $α$ particle is

The correct option is A $1.1 \times 10^{- 7} s$
The time period of revolution of $α$ -particle is:
$T = \frac{2 π m}{q B} = \frac{2 π r}{v}$

$= \frac{2 \times 3.14 \times 0.45}{2.6 \times 10^{7}} = 1.08 \times 10^{- 7} s e c$