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Question

An alternating current of 1.5mA and angular frequency 300 rad/sec flows through a 10KΩ resistor and a 0.50μF capacitor in series. find the rms voltage across the capacitor and impedance of the circuit?

A
1.2×104Ω; 10V
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B
104Ω; 104V
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C
1.0×1.04Ω; 50V
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D
10Ω;10v
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Solution

The correct option is A 1.2×104Ω; 10V
Vrms across capacitor=Irms×C
=1.5×103×1ωC
=1.5×103×1300×0.5×106
=1×10
10V
Impedance of circuit is
Z=R2+X2C
=(10×103)2+(11.5×104)2
=108+108(1.5)2
=1.2×104Ω

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