Question

An alternating current of rms value $10A$ is passed through a $12\Omega$ resistor. The maximum potential difference across the resistor is :

• A. $20V$
• B. $90V$
• C. $169.68V$
• D. None of these

Answer 1

The correct option is C $169.68V$

$I_0=I_{rms}\times \sqrt{2}$
$=10\sqrt{2}A$
$\therefore$ Maximum potential difference $=V_0$
$=12\times 10\sqrt{2}$
$=120\times 14.14$
$=169.68V$