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Question

An alternating e.m.f. of angular frequency is applied across an inductance. The instantaneous power developed in the circuit has an angular frequency

A
ω4
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B
ω2
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C
ω
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D
2ω
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Solution

The correct option is D 2ω

The instantaneous values of emf and current in inductive circuit are given by E=E0 sin ωt and i=i0 sin(ωtπ2)respectively.

So, Pinst=Ei=E0 sinωt× i0 sin(ωtπ2)
=E0i0 sin ωt(sin ωt cosπ2cos ωt sinπ2)
=E0i0 sin ωt cosωt
=12E0i0 sin 2ωt (sin 2ωt=2sin ωt cos ωt)
Hence, angular frequency of instantaneous power is 2ω.


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