An alternating emf given by V-V0sin- t has peak value 10 volt and frequency 50 Hz- The instantaneous emf at t-1600s is -

The correct option is B 5 V V_o=10 f =50 Hz t=1600sec V=10 sin (2π× 50×1600) =10sin(2π12) =5V ...

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Standard XII

Physics

Alternating Current Applied to an Inductor

An alternatin...

Question

An alternating emf given by $V = V_{0} s i n ω t$ has peak value 10 volt and frequency 50 Hz. The instantaneous emf at $t = \frac{1}{600}$ s is :

10 V

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5 \sqrt{3} V

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5 V

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1 V

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Solution

The correct option is B $5 V$
$V_{o} = 10$
$f = 50$ Hz
$t = \frac{1}{600} s e c$
$V = 10 s i n (2 π \times 50 \times \frac{1}{600})$
$= 10 s i n (\frac{2 π}{12})$
$= 5 V$

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An alternating emf given by V=V0sinωt has peak value 10 volt and frequency 50 Hz. The instantaneous emf at t=1600s is :

The correct option is B 5VVo=10f=50 Hzt=1600secV=10sin(2π×50×1600)=10sin(2π12)=5V

An alternating emf given by $V = V_{0} s i n ω t$ has peak value 10 volt and frequency 50 Hz. The instantaneous emf at $t = \frac{1}{600}$ s is :

The correct option is B $5 V$
$V_{o} = 10$
$f = 50$ Hz
$t = \frac{1}{600} s e c$
$V = 10 s i n (2 π \times 50 \times \frac{1}{600})$
$= 10 s i n (\frac{2 π}{12})$
$= 5 V$