The peak value of an alternating emf E given by E-E0 cos - tis 10 V and frequency is 50 Hz- At time t-1600s- the instataneous value of e-m-f- is-

The peak value of an alternating e.m.f. E given by $E = E_{0} cos ω t$ is 10 volt and frequency is 50 Hz. At time $t = (1 / 600)$ sec, the instantaneous value of e.m.f. is

Q. The peak value of an alternating emf is given by

E = E_{0} c o s (w t)

is 10 volt and its frequency is 50 Hz. At a time

t = (\frac{1}{600})

second, the instantaneous value of the emf is:

Q. The peak value of an alternating e.m.f. E is given by

E = E_{0} c o s ω t

is 10 volts and its frequency is 50 Hz. At time

t = \frac{1}{600} s e c,

the instantaneous e.m.f. is

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The peak value of an alternating emf E given by E=E0cosωtis 10V and frequency is 50Hz. At time t=(1600)s, the instataneous value of e.m.f. is:

The correct option is B 5√3VInstantaneous emf is :E=10Cos{2π(50)(1600)}=10cosπ6=10√32=5√3V

The peak value of an alternating emf $E$ given by $E = E_{0} c o s ω t$
is $10 V$ and frequency is $50 H z$ . At time $t = (\frac{1}{600}) s$ , the instataneous value of e.m.f. is:

The correct option is B $5 \sqrt{3} V$
Instantaneous emf is :
$E = 10 C o s {2 π (50) (\frac{1}{600})}$

$= 10 c o s \frac{π}{6}$

$= \frac{10 \sqrt{3}}{2}$

$= 5 \sqrt{3} V$