The peak value of an alternating e-m-f E given by E - E0cos- t is 10 V and frequency is 50 Hz- At time t - 1-600s- the instantaneous value of e-m-f is

The peak value of an alternating e.m.f. E given by $E = E_{0} cos ω t$ is 10 volt and frequency is 50 Hz. At time $t = (1 / 600)$ sec, the instantaneous value of e.m.f. is

Q. The peak value of an alternating e.m.f. E is given by

E = E_{0} c o s ω t

is 10 volts and its frequency is 50 Hz. At time

t = \frac{1}{600} s e c,

the instantaneous e.m.f. is

Q. The peak value of an alternating emf is given by

E = E_{0} c o s (w t)

is 10 volt and its frequency is 50 Hz. At a time

t = (\frac{1}{600})

second, the instantaneous value of the emf is:

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The peak value of an alternating e.m.f E given by E=E0cosωt is 10 V and frequency is 50 Hz. At time t=(1/600)s, the instantaneous value of e.m.f is

The correct option is B 5√3 VE=EocosωtEo=10 Vf=50Hz,ω=2π×50=100πt=1600 secThe instantaneous value of e.m.f =10cos(100π×1600)=10cos(π6)=5√3 V

The peak value of an alternating e.m.f $E$ given by $E = E_{0} cos ω t$ is $10 V$ and frequency is $50 H z$ . At time $t = (1 / 600) s$ , the instantaneous value of e.m.f is

The correct option is B $5 \sqrt{3} V$
$E = E_{o} c o s ω t$
$E_{o} = 10 V$
$f = 50 H z, ω = 2 π \times 50 = 100 π$
$t = \frac{1}{600} s e c$
The instantaneous value of e.m.f $= 10 cos (100 π \times \frac{1}{600}) = 10 cos (\frac{π}{6}) = 5 \sqrt{3} V$