An alternating supply of 220 V is applied across a circuit with resistance 22 Ω and impedance 44 Ω. The power dissipated in the circuit will be
A
1100 W
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
550 W
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2200 W
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(2200/3) W
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B 550 W Here, V = 220 V Resistance, R = 22 Ω Impedance, Z = 44 Ω Current in circuit, I=VZ=220V44Ω=5A Power dissipated in the circuit, P=I2R=(5)2×22=550W