An alternating volatage E-200sin300t volt is applied across a series combination of R-10- and inductance of 800mH- Calculate the impedance of the circuit-

Comparing the given voltage with #160; #160; E = E_o #160; sin(wt) We get #160; #160; w = 300 Given : #160; R = 10Ω #160; #160; ...

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Standard XII

Physics

Impedance Triangle

An alternatin...

Question

An alternating volatage $E = 200 sin (300 t)$ volt is applied across a series combination of $R = 10 Ω$ and inductance of $800$ mH. Calculate the impedance of the circuit.

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Solution

Comparing the given voltage with $E = E_{o} sin (w t)$
We get $w = 300$
Given : $R = 10 Ω$ $L = 800 m H = 0.8 H$
Inductive reactance $X_{L} = w L = 300 \times 0.8 = 240 Ω$
Impedance of circuit $Z = \sqrt{R^{2} + X_{L}^{2}}$
$⟹ Z = \sqrt{10^{2} + 240^{2}} = 240.21 Ω$

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An alternating volatage E=200sin(300t) volt is applied across a series combination of R=10Ω and inductance of 800mH. Calculate the impedance of the circuit.

Comparing the given voltage with E=Eo sin(wt)We get w=300Given : R=10Ω L=800mH=0.8HInductive reactance XL=wL=300×0.8=240ΩImpedance of circuit Z=√R2+X2L⟹ Z=√102+2402=240.21Ω

An alternating volatage $E = 200 sin (300 t)$ volt is applied across a series combination of $R = 10 Ω$ and inductance of $800$ mH. Calculate the impedance of the circuit.

Comparing the given voltage with $E = E_{o} sin (w t)$
We get $w = 300$
Given : $R = 10 Ω$ $L = 800 m H = 0.8 H$
Inductive reactance $X_{L} = w L = 300 \times 0.8 = 240 Ω$
Impedance of circuit $Z = \sqrt{R^{2} + X_{L}^{2}}$
$⟹ Z = \sqrt{10^{2} + 240^{2}} = 240.21 Ω$