An aluminium measuring rod- which is correct at 5 - C measures the length of a line as 80 cm at 45 - C - If thermal coefficient of linear expansion of aluminium is 2-50 - 10 - 5 - - C the correct length of the line

The correct option is A 80.08 L_t = L_0[ 1 + αΔ t] L_t = 80[ 1 + 2.5 ×10^ 5× 40] L_t = 80[ 1 + 100 ×10^ 5] L_t = 80 × 1.001 L_t = 10 ...

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Standard XII

Physics

Thermal Expansion

An aluminium ...

Question

An aluminium measuring rod, which is correct at $5^{\circ} C$ measures the length of a line as 80 cm at $45^{\circ} C$ . If thermal coefficient of linear expansion of aluminium is $2.50 \times 10^{- 5} /^{\circ} C$ the correct length of the line

80.08

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79.92

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81.12

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Solution

The correct option is A 80.08
$L_{t} = L_{0} [1 + α Δ t]$
$L_{t} = 80 [1 + 2.5 \times 10^{- 5} \times 40]$
$L_{t} = 80 [1 + 100 \times 10^{- 5}]$
$L_{t} = 80 \times 1.001$
$L_{t} = 10.01 \times 8 = 80.08 c m$
Hence,
option $(A)$ is correct answer.

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An aluminium measuring rod, which is correct at 5∘C measures the length of a line as 80 cm at 45∘C . If thermal coefficient of linear expansion of aluminium is 2.50×10−5/∘C the correct length of the line

The correct option is A 80.08Lt=L0[1+αΔt]Lt=80[1+2.5×10−5×40]Lt=80[1+100×10−5]Lt=80×1.001Lt=10.01×8=80.08cmHence,option (A) is correct answer.

An aluminium measuring rod, which is correct at $5^{\circ} C$ measures the length of a line as 80 cm at $45^{\circ} C$ . If thermal coefficient of linear expansion of aluminium is $2.50 \times 10^{- 5} /^{\circ} C$ the correct length of the line

The correct option is A 80.08
$L_{t} = L_{0} [1 + α Δ t]$
$L_{t} = 80 [1 + 2.5 \times 10^{- 5} \times 40]$
$L_{t} = 80 [1 + 100 \times 10^{- 5}]$
$L_{t} = 80 \times 1.001$
$L_{t} = 10.01 \times 8 = 80.08 c m$
Hence,
option $(A)$ is correct answer.