Question

An ammeter has a resistance of G ohm and a range of I amp. The value of resistance used in parallel to convert it into an ammeter of range nI amp is

• A. nG
• B. (n - 1)G
• C. G/n
• D. G/(n - 1)

Answer 1

Answer: (D)

G/(n - 1)

We know that resistance shunt is: $S=\frac{I_g}{I-I_g}G$
Here, $I_g=I$ and $I=nI$
Thus, $S=\frac{I}{nI-I}G=\frac{G}{(n-1)}$