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Specific Heat Capacity

An amount of ...

Question

An amount of water of mass $20$ g at $0^{o}$ C is mixed with $40$ g of water at $10^{o}$ C, then the final temperature of mixture is :

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Solution

We know,
$T^{'} = \frac{m_{1} T_{1} + m_{2} T_{2}}{m_{1} + m_{2}} = \frac{20 \times 0 + 40 \times 10}{20 + 40} = 6.6 ° C$
is the required final temperature.

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