Question

If $10$g of ice at $0^o$C is mixed with $10$g of water at ${10}^o$C, the final temperature is

• A. $10\times 80=10(10-f)+10(t-0)$
• B. $t=5^{o}C$
• C. $t=0^{o}C$
• D. $10\times 80+10(10-t)$

Answer 1

The correct option is C $t=0^{o}C$

Heat required to melt $10g$ of ice $=10\times 80=800cal$

Heat released by water at ${10}^{o}C$ when cools to $0^{o}C$ $=10\times 1\times (10-0)=100cal$

Required heat is much more than released heat

So, final temperature is $0^{o}C$