An ancient coin is tossed a $100$ times out of which $40$ tosses resulted in heads. What are the odds in favor of getting a tail?

3 : 2

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2 : 3

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3 : 5

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5 : 3

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Solution

The correct option is A $3 : 2$
We have,
Total number of tosses $= 100$
Number of heads $= 40$
Number of tails $= 100 - 40 = 60$
Odds in favor of tails $= \frac{Number of favorable outcome}{Number of unfavorable outcome}$
$= \frac{60}{40} = \frac{3}{2}$

Which can be written as $3 : 2$ .

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An ancient coin is tossed a 100 times out of which 40 tosses resulted in heads. What are the odds in favor of getting a tail?

The correct option is A 3:2We have, Total number of tosses =100 Number of heads =40 Number of tails =100−40=60 Odds in favor of tails =Number of favorable outcomeNumber of unfavorable outcome =6040=32 Which can be written as 3:2.

An ancient coin is tossed a $100$ times out of which $40$ tosses resulted in heads. What are the odds in favor of getting a tail?

The correct option is A $3 : 2$
We have,
Total number of tosses $= 100$
Number of heads $= 40$
Number of tails $= 100 - 40 = 60$
Odds in favor of tails $= \frac{Number of favorable outcome}{Number of unfavorable outcome}$
$= \frac{60}{40} = \frac{3}{2}$

Which can be written as $3 : 2$ .