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Standard XII

Mathematics

Distance of a Point from Coordinate Axes

An ant is mov...

Question

An ant is moving along the line $5 y = - 6 x + 30$ at a rate of $2$ units per second. If the ant starts at the $y$ -intercept and moves to the right along this line, find the time in seconds it will take for the ant to reach the $x$ -axis.

2.50

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3.25

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3.76

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3.91

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7.81

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Solution

The correct option is D $3.91$
$X$ -intercept is $5$ and the $Y$ - intercept is $6$ .
The distance ant travels is $\sqrt{6^{2} + 5^{2}} = \sqrt{36 + 25} = \sqrt{61} = 7.81$
Time taken is equal to $7.81 / 2 = 3.91$ .

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An ant is moving along the line 5y=−6x+30 at a rate of 2 units per second. If the ant starts at the y-intercept and moves to the right along this line, find the time in seconds it will take for the ant to reach the x-axis.

The correct option is D 3.91X-intercept is 5 and the Y- intercept is 6.The distance ant travels is √62+52=√36+25=√61=7.81Time taken is equal to 7.81/2=3.91.

An ant is moving along the line $5 y = - 6 x + 30$ at a rate of $2$ units per second. If the ant starts at the $y$ -intercept and moves to the right along this line, find the time in seconds it will take for the ant to reach the $x$ -axis.

The correct option is D $3.91$
$X$ -intercept is $5$ and the $Y$ - intercept is $6$ .
The distance ant travels is $\sqrt{6^{2} + 5^{2}} = \sqrt{36 + 25} = \sqrt{61} = 7.81$
Time taken is equal to $7.81 / 2 = 3.91$ .