Question

An ant moves along the sides of a square room of length 4 m starting from A and reaches the opposite corner C by travelling from A to B and from B to C. If the time taken is 2 s, the average velocity of the particle is :

• A. $4m{s}^{-1}$
• B. $2\sqrt{2}m{s}^{-1}$
• C. $2m{s}^{-1}$
• D. $4\sqrt{2}m{s}^{-1}$

Answer 1

The correct option is B $2\sqrt{2}m{s}^{-1}$

Displacement of the ant is the length of the diagonal of the square.
$s=\sqrt{4^2+4^2}=4\sqrt{2}$
Average velocity $=\frac{displacement}{time}$
v $=\frac{4\sqrt{2}}{2}=2\sqrt{2}m/s$