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Question

# An aqueous solution freezes at 272.4 K while pure water freezes at 273 K. Determine the depression in freezing point of solution .[Given : Kf=1.86Kkgmolâˆ’1, Kb=0.512Kkgmolâˆ’1 and vapour pressure of water at 298 K = 23.756 mm of Hg].

A
0.68
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B
0.43
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C
0.60
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D
0.326
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Solution

## The correct option is C 0.60Given that,The freezing point of the solution, Ts=272.4 KThe freezing point of the pure water, Tf=273 KNow,Depression in freezing point of the solution, ΔTf=Tf−Ts=273−272.4=0.6 K

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