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Depression in Freezing Point

An aqueous so...

Question

An aqueous solution freezes at 272.4 K while pure water freezes at 273 K. Determine the depression in freezing point of solution .

[Given : $K_{f} = 1.86 K k g m o l^{- 1}, K_{b} = 0.512 K k g m o l^{- 1}$ and vapour pressure of water at 298 K = 23.756 mm of Hg].

A

0.68

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B

0.43

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C

0.60

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D

0.326

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Solution

The correct option is C $0.60$
Given that,
The freezing point of the solution, $T_{s} = 272.4 K$
The freezing point of the pure water, $T_{f} = 273 K$
Now,
Depression in freezing point of the solution, $Δ T_{f} = T_{f} - T_{s} = 273 - 272.4 = 0.6 K$

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