Question

An aqueous solution of 6.3 g oxalic acid dihydrate is made up to 250 mL. The volume of 0.1 N NaOH required to completely neutralize 10 mL of this solution is :

• A. 40 mL
• B. 20 mL
• C. 10 mL
• D. 4 mL

Answer 1

The correct option is A 40 mL

n-factor for $H_2{C}_2{O}_4.2H_{2}O$=2

Normality =$\frac{weight\times 2\times 1000}{molecularweight\times 250}$ = $\frac{6.3\times 2000}{126\times 250}$ =0.4

equating no. of equivalents :

$N_1{V}_1=N_2{V}_2$

$0.4\times 10=V_2\times 0.1$

Volume ($V_2$)= 40mL.

Hence, the correct option is $A$