An aqueous solution of glucose is $10 %$ . The volume in which $1$ g mol of it is dissolved will be :

0.9 L

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9 L

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1.8 L

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18 L

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Solution

The correct option is B $1.8 L$
Concentration of Glucose ( $C_{6} H_{12} O_{6}$ ) = $10 g i n 100 m L$

Molecular wt. of glucose = $180 g / m o l$

To dissolve $180$ g, solvent required = $\frac{100}{10} \times 180 = 1800 m L = 1.8 L$

Therefore, option $C$ is correct.

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