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Question

An arithmetic sequence has 6th term as 52 and 15th term as 142. Find a & d .


A

2,10

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B

10,2

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C

2,20

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D

20,2

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Solution

The correct option is A

2,10


given a6 = a + ( 6 - 1 ) d = 52

a + 5d = 52 -------------------------------------------------------------------(i)

and a15 = a + ( 15 - 1 ) d = 142

a + 14d = 142 ----------------------------------------------------------------(ii)

Solving (i) and (ii)

(ii) – (i) 9d = 90

d = 10

Substituting d=10 in (i)

a+50 = 52

a = 2


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