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An aromatic o...

Question

An aromatic organic compound [A] on heating with ${N H}_{3}$ and ${C u}_{2} O$ at high pressure gives [B]. The compound [B] on treatment with ice cold solution of ${N a N O}_{2}$ and $H C L$ gives [C].Which on heating with $C u / H C l$ gives compound [A] again. Identify the compounds [A], [B] and [C]. Write the name of the reaction for the conversion of [B] to [C] ?

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Solution

Conversion of $B$ to $C$ is called Sand-Meyer reaction.

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