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Question
An arrow 2.5 cm high is placed at a distance of 25 cm from a diverging mirror of focal length of 20 cm-find the nature, position and size of the image formed
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Solution
H1
= +2.5cm
u
= -25cm
f
= +20cm
1/f
= 1/v + 1/u
1/20
= 1/v -1/25
1/v
= 1/20 + 1/25
1/v
= 9/100
v
= +11.11 cm
m
= h2/h1 = -v/u
h2/2.5
= -11.11/-25
h2
= +1.11 cm
Hence
the image will be formed at 11.11 cm behind the mirror, which will be virtual,
erect and of 1.11cm size.
H1 = +2.5cm
u = -25cm
f = +20cm
1/f = 1/v + 1/u
1/20 = 1/v -1/25
1/v = 1/20 + 1/25
1/v = 9/100
v = +11.11 cm
m = h2/h1 = -v/u
h2/2.5 = -11.11/-25
h2 = +1.11 cm
Hence the image will be formed at 11.11 cm behind the mirror, which will be virtual, erect and of 1.11cm size.
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