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Question

An article manufactured by a company consists of two parts X and Y. In the process of manufacture of the part X. 9 out of 100 parts may be defective. Similarly 5 out of 100 are likely to be defective in part Y. Calculate the probability that the assembled product will not be defective.

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Solution

Let A= Part X is not defective

Probability of A is P(A)=91100

B=Part Y is not defective.

Probability of B is P(B)=95100

Required probability =P(AB)=P(A)P(B)=91100×95100=864510000

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