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An athlete ru...

Question

An athlete running at 18 kmph alongside a railway track is 480 meters ahead of the engine of a 240 meters long train running at 90 kmph in the same direction. In how much time will the train pass the man?

18 sec

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78 sec

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60 sec

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36 sec

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30 sec

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Solution

The correct option is D
36 sec

Let the distance covered by athlete be `x' before train crosses him $\frac{720 + x}{90}$ = $\frac{x}{18}$

x = 180 m

Time taken = $\frac{(720 + 180) \times 3600}{90 \times 1000}$ = 36 seconds

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An athlete running at 18 kmph alongside a railway track is 480 meters ahead of the engine of a 240 meters long train running at 90 kmph in the same direction. In how much time will the train pass the man?

The correct option is D 36 sec Let the distance covered by athlete be `x' before train crosses him 720+x90 = x18 x = 180 m Time taken = (720+180)×360090×1000 = 36 seconds

The correct option is D
36 sec

Let the distance covered by athlete be `x' before train crosses him $\frac{720 + x}{90}$ = $\frac{x}{18}$

x = 180 m

Time taken = $\frac{(720 + 180) \times 3600}{90 \times 1000}$ = 36 seconds