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Nuclear Fusion

An atom initi...

Question

An atom initially at an energy level $E = - 6.52 e V .$ It absorbs a photon of wavelenght $860 n m$ . What is the internal energy of atom after absorbing photon.

A

5.08 e V

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B

1.44 e V

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C

- 1.44 e V

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D

- 5.08 e V

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Solution

The correct option is D $- 5.08 e V$
$E (e v) = \frac{1240}{860} = 1.44 e V$

$E_{n e t} = - 6.52 + 1.44 = - 5.08 e V$

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