Question

An atom is initially at an energy level $E=-6.52eV$. It absorbs a photon of wavelength $860nm$. The internal energy of atom after absorbing photon is

• A. $5.08eV$
• B. $1.44eV$
• C. $-1.44eV$
• D. $-5.08eV$

Answer 1

The correct option is D $-5.08eV$

$E_1=-6.52eV$
$\lambda =860nm$

$\Delta E=\frac{1240}{860}eV=1.44eV$

Internal energy $=1.44-6.52$
$=-5.08eV$