An atom $X$ has three electrons more than noble gas configuration. What type of ion will it form? Write the formula of its 'carbonate'

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Solution

An atom $X$ has three electrons more than noble gas configuration. Thus, it will lose 3 electrons and form a cation: $X^{3 +}$
The charge on carbonate ion is -2 i.e. ${CO}_{3}^{2 -}$ and hence the formula of its Carbonate is $X_{2} {({CO}_{3})}_{3}$

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An atom X has three electrons more than noble gas configuration. What type of ion will it form? Write the formula of its 'carbonate'

An atom X has three electrons more than noble gas configuration. Thus, it will lose 3 electrons and form a cation: X3+ The charge on carbonate ion is -2 i.e. CO32− and hence the formula of its Carbonate is X2(CO3)3

An atom $X$ has three electrons more than noble gas configuration. What type of ion will it form? Write the formula of its 'carbonate'

An atom $X$ has three electrons more than noble gas configuration. Thus, it will lose 3 electrons and form a cation: $X^{3 +}$
The charge on carbonate ion is -2 i.e. ${CO}_{3}^{2 -}$ and hence the formula of its Carbonate is $X_{2} {({CO}_{3})}_{3}$