Question

An atom X has three electrons more than the noble gas configuration. What type of ion will it form ? Write the formula of its (i) sulphate (ii) nitrate (iii) phosphate (iv) carbonate (v) hydroxide.

Answer 1

• X has three electrons more than the noble gas configuration ​
• That is the valence electrons in the valence shell is 3, hence the valency of X is 3

The formula of its

(i) sulfate

• Sulfate ion has a valency of 2
• The chemical formula of X's sulfate is $X_2{\left(S{O}_4\right)}_3$ ​

(ii) nitrate

• ​Nitrate ion has a valency of 1
• The chemical formula of X's nitrate is$X{\left(N{O}_3\right)}_3$

(iii) phosphate

• Phosphate ​ion has a valency of 3
• The chemical formula of X's phosphate is $XP{O}_4$

(iv) carbonate

• Carbonate ​​ion has a valency of 2
• The chemical formula of X's carbonate is $X_2{\left(C{O}_3\right)}_3$

(v) hydroxide.

• ​Hydroxide ​​ion has a valency of 1
• The chemical formula of X's hydroxide is $X{\left(OH\right)}_3$