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Standard XII

Physics

Acceleration

An auto trave...

Question

An auto travelling along a straight road increases its speed from 30.0 m $s^{- 1}$ to 50.0 m $s^{- 1}$ in a distance of 180 m. If the acceleration is constant, how much time elapses while the auto moves this distance?

6.0 s

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4.5 s

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3.6 s

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7.0 s

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Solution

The correct option is B 4.5 s
$u = 30 m / s v = 50 m / s s = 180 m a = c o n s t a n t (g i v e n)$

By third equation of motion, $v^{2} = u^{2} + 2 a s (50)^{2} = (30)^{2} + 2 a (180) a = \frac{40}{3} m / s^{2}$

By first equation of motion, $v = u + a t 50 = 30 + (\frac{40}{9}) t t = \frac{9}{2} = 4.5 s e c$

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A

on a straight road, its speed is

10 m/s

. The car moves with constant acceleration

a {m/s}^{2}

along the road for

T

seconds until it reaches the point

B

, where its speed is

v m/s

. The car travels at this speed for a further

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seconds, when it reaches the point

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An auto travelling along a straight road increases its speed from 30.0 m s−1 to 50.0 m s−1 in a distance of 180 m. If the acceleration is constant, how much time elapses while the auto moves this distance?

The correct option is B 4.5 su=30m/sv=50m/ss=180ma=constant(given)By third equation of motion, v2=u2+2as(50)2=(30)2+2a(180)a=403m/s2By first equation of motion, v=u+at50=30+(409)tt=92=4.5sec

An auto travelling along a straight road increases its speed from 30.0 m $s^{- 1}$ to 50.0 m $s^{- 1}$ in a distance of 180 m. If the acceleration is constant, how much time elapses while the auto moves this distance?