Question

An automobile engine develops 10 kW when rotating at a speed of 1800 rev/min. What torque does it deliver

• A. 53.06 N-m
• B. 440 N-m
• C. 524 N-m
• D. 628 N-m

Answer 1

The correct option is A 53.06 N-m

$Torque=\frac{Power}{AngulurVelocity}$

$=\frac{10\times {10}^3}{1800\times \frac{2\pi }{60}}N-M$

$=53.061NM$