The period of revolution of an earth satellite close to surface of earth is 90 min. The time period of another satellite in an orbit at a distance of three times the radius of earth from its surface will be

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An earth satellite S has an orbit radius which is 4 times that of a communication satellite C. The period of revolution of S is

The correct option is B 8 daysWe know, T2∝R3 RS=4RC T2CR3C=T2SR3S 12R3C=T2S64R3C T2S=64 TS=8 days

An earth satellite $S$ has an orbit radius which is $4$ times that of a communication satellite $C$ . The period of revolution of $S$ is

The correct option is B 8 days
We know,
$T^{2} \propto R^{3}$
$R_{S} = 4 R_{C}$

$\frac{T_{C}^{2}}{R_{C}^{3}} = \frac{T_{S}^{2}}{R_{S}^{3}}$

$\frac{1^{2}}{R_{C}^{3}} = \frac{T_{S}^{2}}{64 R_{C}^{3}}$

$T_{S}^{2} = 64$

$T_{S} = 8$ days