An effort of $120 k g f$ is applied on a machine for movement of a load of $360 k g f$ . The mechanical advantage of the machine is $5$ .

True

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False

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Solution

The correct option is B
False

Given,

Effort = $120 k g f$

Load = $360 k g f$

Mechanical advantage = $\frac{l o a d}{e f f o r t}$ = $\frac{360 k g f}{120 k g f}$ = $3$

Hence, the given statement is false

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