Question

An effort of 500 N is applied through a distance of 0.50 m on a machine, whose efficiency is 90% such that resistance is overcome through a distance of 0.04 m, calculate (i) velocity ratio (ii) mechanical advantage (iii) resistance overcome by the machine ?

Answer 1

Dear Student,

$$\begin{gathered} \mathrm{E}=500\mathrm{N} \\ \mathrm{D}=0.5\mathrm{m} \\ \mathrm{\eta }=90\% \\ \mathrm{d}=0.04\mathrm{m} \\ \left(1\right)\mathrm{Velocity}\mathrm{ratio},\mathrm{VR}=\frac{\mathrm{D}}{\mathrm{d}} \\ \mathrm{VR}=\frac{0.5}{0.04}=12.5 \\ \left(2\right)\mathrm{mechanical}\mathrm{advantage},\mathrm{MA}=\mathrm{\eta }\times \mathrm{VR} \\ \mathrm{MA}=\frac{90}{100}\times 12.5=11.25 \\ \left(3\right)\mathrm{MA}=\frac{\mathrm{L}}{\mathrm{E}} \\ \mathrm{L}=\mathrm{MA}\times \mathrm{E} \\ \mathrm{L}=11.25\times 500=5625\mathrm{N} \end{gathered}$$