An electric bulb is made of tungsten filament of resistance R- It is marked 100W and 230 V- Then- the value of R is -

The correct option is D 529 Ω Power P = V_i = V^2R R=V^2P = (230)^2100 = 529Ω ...

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Standard VIII

Physics

Heating Effect of Electric Current

An electric b...

Question

An electric bulb is made of tungsten filament of resistance $R Ω$ . It is marked $100 W$ and $230 V$ . Then, the value of $R$ is :

300 Ω

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529 Ω

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739 Ω

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100 Ω

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Solution

The correct option is D $529 Ω$
Power $P = V_{i} = \frac{V^{2}}{R}$
$R = \frac{V^{2}}{P} = \frac{(230)^{2}}{100} = 529 Ω$

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An electric bulb is made of tungsten filament of resistance RΩ. It is marked 100W and 230V. Then, the value of R is :

The correct option is D 529ΩPower P=Vi=V2RR=V2P=(230)2100=529Ω

An electric bulb is made of tungsten filament of resistance $R Ω$ . It is marked $100 W$ and $230 V$ . Then, the value of $R$ is :

The correct option is D $529 Ω$
Power $P = V_{i} = \frac{V^{2}}{R}$
$R = \frac{V^{2}}{P} = \frac{(230)^{2}}{100} = 529 Ω$