An electric bulb is rated 500W - 200V. Calculate the magnitude of the current.

100 A

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2.5 A

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0.4 A

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10 A

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Solution

The correct option is B
2.5 A

Given: Power (P) = 500 W and Voltage (V) = 200 V

We know that, Current (I) = $\frac{Power (P)}{Voltage (V)} = \frac{500}{200}$ = 2.5

$∴$ Current (I) = 2.5 A

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An electric bulb is rated 500W - 200V. Calculate the magnitude of the current.

The correct option is B 2.5 A Given: Power (P) = 500 W and Voltage (V) = 200 V We know that, Current (I) = Power (P)Voltage (V)=500200 = 2.5 ∴ Current (I) = 2.5 A

The correct option is B
2.5 A

Given: Power (P) = 500 W and Voltage (V) = 200 V

We know that, Current (I) = $\frac{Power (P)}{Voltage (V)} = \frac{500}{200}$ = 2.5

$∴$ Current (I) = 2.5 A