An electric bulb is rated $750 W - 200 V$ . Calculate the magnitude of current.

200 A

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3.75 A

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15 A

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2 A

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Solution

The correct option is B $3.75 A$
Given, voltage $V = 200 V$ , Power $P = 750 W$ .

Using , $P = V i$

$i = \frac{P}{V} = \frac{750}{200} = 3.75 A$

Hence, $i = 3.75 A$ .

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