An electric bulb of $100 W$ operates at $220 V$ . What is the resistance of its filament?

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Solution

Step: 1 Given
$P o w e r = 100 W V o l t a g e = 220 V$
Step:2 Find resistance
As we know that the power in terms of voltage and resistance is,
$P o w e r = \frac{V^{2}}{R}$
$R e s i s \tan c e = \frac{V^{2}}{P}$
Putting the given values in the formula
$R = \frac{220 \times 220}{100} = 484 o h m' s .$
Hence, the resistance of the filament is $484 o h m s .$

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An electric bulb of 100W operates at 220V. What is the resistance of its filament?

Step: 1 GivenPower=100WVoltage=220VStep:2 Find resistance As we know that the power in terms of voltage and resistance is,Power=V2RResistance=V2PPutting the given values in the formulaR=220×220100=484ohm's.Hence, the resistance of the filament is 484ohms.

An electric bulb of $100 W$ operates at $220 V$ . What is the resistance of its filament?