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Standard XII

Physics

Ideal Gas Equation

An electric b...

Question

An electric bulb of $250 c c$ was sealed off at a pressure $10^{- 3}$ mm of Hg and temperature $27^{0}$ C. The number of molecules present in the gas is

8.02 \times 10^{15}

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6.023 \times 10^{23}

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8.021 \times 10^{23}

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6 \times 10^{22}

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Solution

The correct option is A $8.02 \times 10^{15}$
$P V = n R T n = \frac{P V}{R T} n = \frac{250 \times 10^{- 6} \times 133.33 \times 10^{- 3}}{8.314 \times 300} n = 1.336 \times 10^{- 8} N = n \times N_{A} N = 1.336 \times 10^{- 8} \times 6.022 \times 10^{23} N = 8.02 \times 10^{15}$

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Similar questions

Q. An electric blub of volume 250

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An electric bulb of 250cc was sealed off at a pressure 10−3 mm of Hg and temperature $27^{0}$ C. The number of molecules present in the gas is

The correct option is A 8.02×1015PV=nRTn=PVRTn=250×10−6×133.33×10−38.314×300n=1.336×10−8N=n×NAN=1.336×10−8×6.022×1023N=8.02×1015

An electric bulb of $250 c c$ was sealed off at a pressure $10^{- 3}$ mm of Hg and temperature $27^{0}$ C. The number of molecules present in the gas is

The correct option is A $8.02 \times 10^{15}$
$P V = n R T n = \frac{P V}{R T} n = \frac{250 \times 10^{- 6} \times 133.33 \times 10^{- 3}}{8.314 \times 300} n = 1.336 \times 10^{- 8} N = n \times N_{A} N = 1.336 \times 10^{- 8} \times 6.022 \times 10^{23} N = 8.02 \times 10^{15}$