An electric bulb of r 200ohm and curent 1amphere calculate the power of the bulb amd the energy consumed in kwh if it is glowing for 5hrs ?

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Solution

Dear student,

$G i v e n, R e s i s \tan c e (R) = 200 o h m c u r r e n t (I) = 1 A V o l t a g e = c u r r e n t \times r e s i s \tan c e = 1 \times 200 = 200 V p o w e r = \frac{V^{2}}{R} = \frac{(200)^{2}}{200} = 200 w a t t E n e r g y c o n s u m e d = p o w e r \times t i m e = 200 \times 5 = 1000 w a t t H r = 1 K w H$

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