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Question

An electric current is passed through silver and water voltmeters connected in series. The cathode of the silver voltmeter weighed 0.05 g more at the end of electrolysis. The volume of O2 evolved at the anode of water voltmeter is:

A
5.6 cm3
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B
11.2 cm3
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C
22.4 cm3
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D
2.8 cm3
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Solution

The correct option is D 2.8 cm3
An electric current is passed through silver and water voltmeters connected in series.

The cathode of the silver voltmeter weighed 0.05g more at the end of electrolysis.

The volume of O2 evolved at the anode of water voltmeter is 2.8 cm3

According to faradays second law :

WAgWO2=EAgEO2

0.05gWO2=1088

WO2=0.054×8108=4×103g

8 g of oxygen at STP occupies a volume of 5600cm3

4×103 g of oxygen will occupy a volume of =4×103×56008=2.8 cm3

Hence the correct option is D.

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