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Question

# An electric current is passed through silver and water voltmeters connected in series. The cathode of the silver voltmeter weighed 0.05 g more at the end of electrolysis. The volume of O2 evolved at the anode of water voltmeter is:

A
5.6 cm3
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B
11.2 cm3
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C
22.4 cm3
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D
2.8 cm3
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Solution

## The correct option is D 2.8 cm3An electric current is passed through silver and water voltmeters connected in series. The cathode of the silver voltmeter weighed 0.05g more at the end of electrolysis. The volume of O2 evolved at the anode of water voltmeter is 2.8 cm3According to faradays second law : WAgWO2=EAgEO2 0.05gWO2=1088 WO2=0.054×8108=4×10−3g8 g of oxygen at STP occupies a volume of 5600cm3 ∴4×10−3 g of oxygen will occupy a volume of =4×10−3×56008=2.8 cm3Hence the correct option is D.

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