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Question

An electric current is passed through silver voltameter connected to a water voltameter. The cathode of the silver voltameter weighed 0.108g more at the end of the electrolysis. The volume of O2 evolved at STP :

A
56 cm3
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B
550 cm3
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C
5.6 cm3
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D
11.2 cm3
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Solution

The correct option is C 5.6 cm3
Wt.ofsilverdepositedWt.ofO2produced=Eq.wtofAgEq.wtofO2

0.108Wt.ofO2=1088

Wt. of O2 produced =0.108×8108=0.008g

Now, 32g of O2 produces =22400 ml of O2

0.008g of O2 produces 2240032×0.008=5.6 cm3 of O2

Hence, option C is correct.

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