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Question

An electric dipole consists of two charges of equal magnitude and opposite sign separated by distance 2a, as shown in the figure. the dipole is along the x-axis and is centred at the origin.calculate the electric potential at point P?calculate v at a point far from the dipole?

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Solution

Let, dipole of the K. B at point where +a charge and P at a point,E1=9K(BP)2=9K(x−a)2(E1, towards ¯¯¯¯¯¯¯¯OP)and, A at a point −9 charge where the electric field at point PE2=9K(AP)2 =9K(x+a)2(E2, towards ¯¯¯¯¯¯¯¯PO)Since, E1 and E2 are same line but opposite in direction and E1>E2 ∴ P at a point, The resultant of electric field P.E=E1−E2 =9K[1(x−a)2−1(x+a)2] =9K[(x+a)2−(x−a)2(x−a)2(x−a)2]E=9.4xaK(x2−a2)2 =2pxK(x2−a2)2 [∵P=2aq]Calculation at V at a point four from the dipoleV=Eq =2pxKq(x2−a2)2

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