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Question

# Two charges of equal magnitude 'q' but of opposite sign separated by a distance 2a constitute an electric dipole of dipole moment p. If P is a point at a distance r from the centre of the dipole and the line joining the centre of the dipole to this point makes an angle θ with the axis of the dipole, then the potential at the point P is given by (r≫2a) (Where p=2qa )

A
V=p cosθ4πϵ0r2
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B
V=p cosθ4πϵ0r
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C
V=p sinθ4πϵ0r
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D
V=p cosθ2πϵ0r2
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Solution

## The correct option is A V=p cosθ4πϵ0r2 For the given situation, diagram can be drawn as follows As shown in figure component of dipole moment along the line OP will be p′=pcosθ. Hence electric potential at point P will be V=14πϵ0.p cosθr2

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