An electric dipole is placed at an angle of 30o with an electric field of intensity 2-105NC-1- It experiences a torque of 4Nm- Calculate the charge on the dipole if the dipole length is 2cm -

The correct option is D 2mC Torque τ⃗ ⃗ ⃗ ⃗#⃗1⃗6⃗0⃗;⃗ =p⃗×E⃗ =pEsinθ #160; 4=p× 2× 10 ^ 5 ×sin 30 ^ o or p= 4 2× 10 ^ 5 ×sin 30 ^ o # ...

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Standard XII

Physics

Electric Field Due to a Dipole at a General Point in Space

An electric d...

Question

An electric dipole is placed at an angle of $30^{o}$ with an electric field of intensity $2 \times 10^{5} N C^{- 1}$ . It experiences a torque of $4 N m$ . Calculate the charge on the dipole if the dipole length is $2 c m$ :

8 m C

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4 m C

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8 μ C

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2 m C

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Solution

The correct option is D $2 m C$
Torque $\to τ = \to p \times \to E = p E sin θ$
$4 = p \times 2 \times 10^{5} \times sin 30^{o}$
or $p = \frac{4}{2 \times 10^{5} \times sin 30^{o}} = 4 \times 10^{- 5} C m$
$q = \frac{p}{l} = \frac{4 \times 10^{- 5}}{0.02} = 2 \times 10^{- 3} C = 2 m C$

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An electric dipole is placed at an angle of 30o with an electric field of intensity 2×105NC−1. It experiences a torque of 4Nm. Calculate the charge on the dipole if the dipole length is 2cm :

The correct option is D 2mCTorque →τ=→p×→E=pEsinθ4=p×2×105×sin30oor p=42×105×sin30o=4×10−5Cmq=pl=4×10−50.02=2×10−3C=2mC

An electric dipole is placed at an angle of $30^{o}$ with an electric field of intensity $2 \times 10^{5} N C^{- 1}$ . It experiences a torque of $4 N m$ . Calculate the charge on the dipole if the dipole length is $2 c m$ :

The correct option is D $2 m C$
Torque $\to τ = \to p \times \to E = p E sin θ$
$4 = p \times 2 \times 10^{5} \times sin 30^{o}$
or $p = \frac{4}{2 \times 10^{5} \times sin 30^{o}} = 4 \times 10^{- 5} C m$
$q = \frac{p}{l} = \frac{4 \times 10^{- 5}}{0.02} = 2 \times 10^{- 3} C = 2 m C$