An electric dipole is placed at an angle of 30° with an electric field intensity of 2 × 105 N/C. It experiences a torque equal of 4 Nm. The charge on the dipole, if the dipole length is 2 cm, is
Step 1: Given that:
Angle θ=300
Electric field (E) = 2×105 N/C
Torque(τ) = 4Nm
Dipole length (l ) = 2cm = 2×10−2m
Step 2: Calculation of charge on the dipole:
We know that,
When an electric dipole is placed in a uniform electric field, it experiences a torque(τ), given by:
τ=pEsinθ
Where,
p=dipolemoment
=q×l
Therefore, torque will be:
τ=qlEsinθ
q=τlEsinθ
Putting all the values, we getq=4Nm2×10−2m×2×105NC−1sin300
q=44×103×12
q=2×10−3C
q=2mC
Thus,