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Question

An electric dipole is placed at an angle of 30° with an electric field intensity of 2 × 105 N/C. It experiences a torque equal of 4 Nm. The charge on the dipole, if the dipole length is 2 cm, is


A
5 mC
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B
7 μC
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C
8 mC
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D
2 mC
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Solution

Step 1: Given that:

Angle θ=300

Electric field (E) = 2×105 N/C

Torque(τ) = 4Nm

Dipole length (l ) = 2cm = 2×102m

Step 2: Calculation of charge on the dipole:

We know that,

When an electric dipole is placed in a uniform electric field, it experiences a torque(τ), given by:

τ=pEsinθ

Where,

p=dipolemoment

=q×l

Therefore, torque will be:

τ=qlEsinθ

q=τlEsinθ

Putting all the values, we get

q=4Nm2×102m×2×105NC1sin300

q=44×103×12

q=2×103C

q=2mC

Thus,
The charge on the dipole is 2mC .

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