An electric dipole is placed at an angle of 30° with an electric field intensity of2×105N/C. It experiences a torque equal to 4Nm. The charge on the dipole, if the dipole length is 2cm, is
A
5mC
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B
7μC
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C
8mC
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D
2mC
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Solution
The correct option is D2mC Torque on electric dipole placed in electric field is, τ=PEsinθτ=qlEsinθ4=q×2×10−2×2×105sin30°⇒q=2mC