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Question

An electric dipole moment ¯p=(2.0^i+3.0^j)μCm is placed in a uniform electric field ¯E=(3.0^i+2.0^k)×105NC1

A
The torque that E exerts on p is (0.6^i0.4^j0.9^k)Nm
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B
The potential energy of the dipole is –0.6 J.
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C
The potential energy of the dipole is 0.6 J.
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D
If the dipole is rotated in the electric field, the maximum potential energy of the dipole is 1.3 J.
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Solution

The correct options are
A The torque that E exerts on p is (0.6^i0.4^j0.9^k)Nm
B The potential energy of the dipole is –0.6 J.
Torque is given by,
J=P×E
=∣ ∣ ∣^i^j^k230302∣ ∣ ∣×105×106
=(6^i4^j9^k)×101
=(0.6^i0.4^j0.9^k)Nm1
U=P.E
=[2(3)+3(0)+(0)(2)×105×106]
=0.6J
Umax=PE
=22+32×92+42×1056
=13×85×101
=3.3J

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